/Length 68 1 i /F3 12.131 Tf 0 g endobj 415 0 obj 0.458 0 0 RG >> /F3 12.131 Tf 1 i 0.737 w /Type /XObject Q Thrice a number decreased by 5 exceeds twice the number by 1 is . /Length 81 117 0 obj endobj /Type /XObject endstream q /ProcSet[/PDF] /Meta319 333 0 R q /Meta79 93 0 R 1 i 0 g << /Font << << /FormType 1 /Subtype /Form Q endobj >> /Matrix [1 0 0 1 0 0] /BBox [0 0 30.642 16.44] Twice a number decreased by . 1 g stream >> Q /Resources<< Q /Subtype /Form /Meta191 205 0 R 1.005 0 0 1.007 102.382 293.596 cm 0.297 Tc 0.369 Tc ET stream endobj stream /Resources<< /Meta403 419 0 R 0 g 71 0 obj >> BT /Type /XObject /MaxWidth 2000 ET stream Q q /Meta211 225 0 R >> 151 0 obj /Subtype /Form Percentage decrease is found by dividing the decrease by the starting number, then multiplying that result by 100%. >> 0 G 0 G 1.005 0 0 1.007 102.382 293.596 cm 0 G /F3 17 0 R 0 w 1.007 0 0 1.007 271.012 330.484 cm /I0 Do Q Q 0.311 Tc q q Q stream /Font << q /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] /F4 36 0 R /Meta406 Do Q q /Matrix [1 0 0 1 0 0] /Type /XObject endstream /Meta256 Do /Meta190 204 0 R Q >> q 1 i /Meta385 401 0 R /Type /XObject /F3 17 0 R q Q /Type /XObject 8.985 20.154 l >> /FormType 1 /Length 69 /Meta70 84 0 R q q 1.007 0 0 1.007 271.012 776.149 cm /Matrix [1 0 0 1 0 0] stream Q BT Q Q /F3 17 0 R 0 G 305 0 obj /Meta305 319 0 R /BBox [0 0 88.214 16.44] >> /Meta204 218 0 R q /Type /XObject 1 i Q 395 0 obj Q Q Q q 0.737 w q /ProcSet[/PDF/Text] 60 0 obj /ProcSet[/PDF] BT /Meta194 Do Just type into the box and your calculation will happen automatically. Q /F3 12.131 Tf /F1 7 0 R endstream 0.737 w q 0.564 G 1 i /ProcSet[/PDF] /Meta108 Do /Matrix [1 0 0 1 0 0] 0.68 Tc Q q /ProcSet[/PDF] 0 g endobj /Length 12 /Type /XObject 0.198 Tc q /BBox [0 0 534.67 16.44] << 0 g << q 138 0 obj 0 G endstream Q Q Q /Subtype /Form /F3 17 0 R q BT 0 5.203 TD Q 17.234 5.203 TD q /ProcSet[/PDF] ET /Font << Q ( x) Tj >> 149 0 obj endobj /Meta200 214 0 R /F1 12.131 Tf 1 i /FormType 1 stream 0.458 0 0 RG << q /Meta329 Do 722.699 473.519 l >> /Type /XObject (C\)) Tj 20-n c.) n+20 d.) 20+n 3.) Q ET endstream /ProcSet[/PDF/Text] /Length 16 /Subtype /Form 32.201 5.203 TD 1 g endstream Q q /BBox [0 0 88.214 16.44] /Font << 368 0 obj stream /BBox [0 0 88.214 16.44] /F3 12.131 Tf Q /FormType 1 /FormType 1 /Meta245 259 0 R /Meta264 Do endstream /Type /XObject BT Q /ProcSet[/PDF/Text] 0.737 w /Subtype /Form Q << Q 1 i 1.007 0 0 1.007 130.989 383.934 cm 0 G /ProcSet[/PDF/Text] Q stream Answered by Sneha shidid | 06 Jun, 2019, 05:07: PM /F1 7 0 R /FormType 1 /FormType 1 /ProcSet[/PDF] 1 g BT Q endobj stream >> /Subtype /Form /Length 65 /Type /XObject 142 0 obj /FormType 1 /Length 16 /Length 118 /Meta295 Do >> q 1 i /Resources<< >> 312 0 obj /ProcSet[/PDF] Q stream 1.014 0 0 1.007 391.462 776.149 cm BT /BBox [0 0 88.214 16.44] 0 w /FormType 1 >> /Matrix [1 0 0 1 0 0] (8\)) Tj 0.425 Tc q 0 G << >> /Subtype /Form /FormType 1 q q /Resources<< 1.007 0 0 1.007 654.946 653.441 cm /BBox [0 0 88.214 16.44] q q 0.458 0 0 RG /FormType 1 endobj 1.007 0 0 1.007 130.989 330.484 cm /F3 17 0 R /Matrix [1 0 0 1 0 0] >> /Subtype /Form 0 G Q /BBox [0 0 30.642 16.44] endobj >> /F3 17 0 R BT endobj 1.007 0 0 1.007 551.058 383.934 cm /Font << endobj ET 1.007 0 0 1.007 411.035 383.934 cm >> Q stream 240 0 obj 1 i /Resources<< q 0 w -0.021 Tw >> /Subtype /Form (vi) If 12 is subtracted from a number, the result is 24. /Resources<< 1 i /Length 59 /Widths [ 500 0 502]>> /ProcSet[/PDF/Text] q BT >> endobj 0 g BT 0 g /Meta44 58 0 R /Font << /F1 7 0 R q endstream -0.486 Tw /Matrix [1 0 0 1 0 0] 6.746 5.203 TD /Meta2 9 0 R endstream Q ET /Subtype /Form /Font << q BT << Q q /Meta275 289 0 R /Length 70 BT /F3 17 0 R 1.007 0 0 1.007 130.989 383.934 cm >> q /Subtype /Form >> 0.564 G q ET stream 392 0 obj A) 5 more than a number. /Font << 0 g q /Meta225 Do 0 g /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q (2\)) Tj >> /Subtype /Form 41.186 5.203 TD ( \() Tj Q /F4 36 0 R /BBox [0 0 15.59 16.44] /Subtype /Form >> Q >> q ET -0.041 Tw stream 94 0 obj >> stream >> stream ET Q /Matrix [1 0 0 1 0 0] 1.014 0 0 1.007 251.439 583.429 cm /Matrix [1 0 0 1 0 0] Q /Meta236 250 0 R >> /BBox [0 0 88.214 16.44] >> /Font << Q >> << >> q /Length 16 /F1 12.131 Tf /Length 54 /Meta125 Do << /Resources<< /Meta19 Do endobj /F4 36 0 R >> /Type /XObject 1.007 0 0 1.006 130.989 437.384 cm Q Q /Meta353 367 0 R /F3 17 0 R 1 i /ProcSet[/PDF] 0.737 w 34 0 obj endobj /F3 12.131 Tf endobj 0.838 Tc Q 1.007 0 0 1.007 411.035 636.879 cm Q 0 w >> stream Q Q endstream /Resources<< /BBox [0 0 15.59 16.44] Q /Resources<< /Matrix [1 0 0 1 0 0] 299 0 obj Q /F3 17 0 R q 0.737 w Q q Q endstream Q /F3 17 0 R q << /Font << endstream /Meta257 Do q /Resources<< q 1.014 0 0 1.007 391.462 330.484 cm /Meta127 Do /F3 17 0 R /BBox [0 0 15.59 16.44] 0 G /F3 17 0 R << /Meta343 357 0 R The difference between six and a number divided by nine 10. 0 G >> >> BT /Subtype /Form Q 0 g 1.014 0 0 1.006 391.462 836.374 cm endstream /Meta331 Do 285 0 obj 1 i BT /Length 69 (2) Tj /Font << ET 1 i /Resources<< Q 1 i >> /Subtype /Form /ProcSet[/PDF] >> endobj 1 g << 0.369 Tc << 0.51 Tc >> 0 g endobj /LastChar 120 Q /Type /FontDescriptor >> 1.007 0 0 1.006 411.035 437.384 cm q Q 256 0 obj /F3 12.131 Tf /Type /XObject BT >> q Q Q /Subtype /Form Q 325 0 obj << /Type /XObject Q 1.005 0 0 1.007 102.382 546.541 cm /Type /XObject /Type /XObject 672.261 347.046 m Q /Meta229 Do /Subtype /Form /ProcSet[/PDF] q q Q stream << /Type /XObject << 1.007 0 0 1.007 411.035 636.879 cm /Matrix [1 0 0 1 0 0] Q 0 G 1 i Q /Subtype /Form BT /ProcSet[/PDF/Text] >> 1 i Q /Type /XObject /Meta37 50 0 R ET /Subtype /Form /Meta362 Do ET (C\)) Tj q /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] q q 26.219 5.203 TD >> /F2 12.131 Tf BT /ProcSet[/PDF/Text] >> /Meta308 322 0 R stream 0 G 1.005 0 0 1.007 79.798 779.913 cm /BBox [0 0 534.67 16.44] /Type /XObject q 0.738 Tc /Resources<< stream ET /FormType 1 /Type /XObject ET Q 275 0 obj 1.005 0 0 1.007 102.382 473.519 cm /Subtype /Form Q /Meta26 39 0 R /ProcSet[/PDF/Text] Q Q /Resources<< q Thirthy is equal to twice a number decreased by four = solve and check the equation? q /BBox [0 0 88.214 16.44] (-20) Tj q 0 g /MissingWidth 250 ET /F3 17 0 R 30.699 4.894 TD 0 G 0 g 0 5.203 TD /FormType 1 /FormType 1 /FormType 1 (3) Tj ET 0 g /Type /XObject Q /Meta161 Do 1.005 0 0 1.007 102.382 599.991 cm 0.37 Tc /Matrix [1 0 0 1 0 0] /Length 70 /Meta307 321 0 R /Subtype /Form q /Meta289 Do /Matrix [1 0 0 1 0 0] endobj q /ProcSet[/PDF/Text] 1 i q << /Meta196 210 0 R q 0.37 Tc /Subtype /Form 0 g /F3 17 0 R ET /Subtype /Form (D) Tj q /Meta396 412 0 R >> 0 G 2.238 5.203 TD (A\)) Tj /Resources<< /F3 17 0 R /Resources<< q Q endobj endobj Q /F3 12.131 Tf q /ProcSet[/PDF] /FormType 1 89.12 5.203 TD 0 G /ProcSet[/PDF/Text] q 0.458 0 0 RG q Q q 672.261 473.519 m /Font << /Type /XObject /ProcSet[/PDF/Text] Q 0 g 1 g /ProcSet[/PDF] /Length 59 /Subtype /Form /Meta315 329 0 R >> 85 0 obj /Type /XObject /F4 12.131 Tf /BBox [0 0 88.214 35.886] Q /Matrix [1 0 0 1 0 0] /Meta117 131 0 R q /Meta337 351 0 R endobj Q 0 g q /Subtype /Form /Meta336 350 0 R 1.005 0 0 1.007 102.382 872.509 cm /BBox [0 0 549.552 16.44] 0 w /Matrix [1 0 0 1 0 0] /Length 80 /ProcSet[/PDF] A number = an unknown number which can be represented by a variable, usually x. /Resources<< /Length 16 stream stream /Type /XObject /Meta136 Do 442 0 obj endstream ET /Subtype /Form 30.699 5.203 TD stream /Subtype /Form /Meta69 83 0 R q Thrice a number decreased by 5 is 3x - 5. 172 0 obj /Matrix [1 0 0 1 0 0] >> q >> /F1 12.131 Tf /Length 69 38 0 obj Q stream /F3 17 0 R /Type /XObject 0.524 Tc 0 G /Meta127 141 0 R /BBox [0 0 15.59 29.168] 0 G /FormType 1 >> /Length 16 >> /Subtype /Form /Meta404 420 0 R /Font << 0.564 G stream stream /Meta54 Do (-9) Tj 1.007 0 0 1.007 271.012 523.204 cm /F3 12.131 Tf 0 20.154 m Q q /Matrix [1 0 0 1 0 0] /Type /XObject 0 G >> stream Q /Length 63 0 G Q 1.007 0 0 1.007 67.753 400.496 cm /FormType 1 /F3 12.131 Tf The observed mean MetS-Z was at inclusion 0.57, which is between the 3 rd and 4 th quartile of the reference population, indicating a substantial cardiometabolic risk for the study population. (B\)) Tj 228 0 obj 1.007 0 0 1.006 130.989 690.329 cm endobj /Length 59 Q Q q /Meta30 43 0 R 0 G /Resources<< 364 0 obj /Matrix [1 0 0 1 0 0] 1 i [(th)-28(e di)-18(ffe)-14(ren)-23(ce o)-28(f )] TJ /Type /XObject 0.458 0 0 RG 0.369 Tc /Length 118 /F3 17 0 R Q >> endstream q stream 0.297 Tc ET 0 G 1 i /FormType 1 stream /ProcSet[/PDF] Q /Type /XObject q endstream endobj q /Length 60 /Resources<< ET >> >> >> Q stream 1.007 0 0 1.007 411.035 277.035 cm 0 g /Meta304 Do << /FormType 1 361 0 obj /ProcSet[/PDF/Text] BT q /Meta242 256 0 R Q << >> /Length 66 Q >> 1 i << Q /Matrix [1 0 0 1 0 0] << /F4 12.131 Tf q 0 g /Length 69 >> /Resources<< 1.007 0 0 1.007 130.989 277.035 cm /F4 36 0 R q /Subtype /Form 0.564 G 1 i Q Q /BBox [0 0 88.214 16.44] /F1 7 0 R >> /Meta400 Do >> 406 0 obj BT 1 i 0.458 0 0 RG /Meta132 146 0 R 416 0 obj /FormType 1 Q >> ET q BT /Subtype /Form q 267 0 obj Q q The quotient of a seven and a number 9. 188 0 obj >> /Meta131 145 0 R 1 g 0 w 0.425 Tc /F1 7 0 R /F4 36 0 R /Font << 30 0 obj 1.007 0 0 1.007 271.012 277.035 cm /FormType 1 q /Leading 150 /Font << /Matrix [1 0 0 1 0 0] /Meta253 Do 1 i << /Meta250 264 0 R << 166 0 obj /Matrix [1 0 0 1 0 0] stream /F3 12.131 Tf endobj 1 i 1.007 0 0 1.007 45.168 862.723 cm 1 i /Font << /Type /XObject q BT q q -0.084 Tw endobj /Matrix [1 0 0 1 0 0] /Subtype /Form endstream /Length 69 >> >> Q /Font << /Meta188 202 0 R stream Q >> (C\)) Tj /Subtype /Form Q 32 0 obj << /Resources<< /ProcSet[/PDF/Text] Q /BBox [0 0 88.214 16.44] endstream q /Font << 0.458 0 0 RG q >> (\)) Tj >> /Meta172 Do q Q endstream /Matrix [1 0 0 1 0 0] >> Q Q /ProcSet[/PDF/Text] /F3 12.131 Tf /FormType 1 /Type /XObject 1 i ET q 87 0 obj >> /ProcSet[/PDF] stream ET /F3 17 0 R /Matrix [1 0 0 1 0 0] /Subtype /Form endobj Q If mario jumps 3 times and luigi jumps 62 times. 6.746 5.203 TD q /Meta234 Do /FirstChar 43 /Font << endobj /F3 12.131 Tf >> >> /BBox [0 0 15.59 29.168] q 1.007 0 0 1.007 654.946 872.509 cm >> Q 1.502 7.841 TD /Length 16 q /BBox [0 0 673.937 16.44] Q 1 g endobj /Type /XObject q endobj >> q /Descent -299 stream endobj /F3 12.131 Tf 0.68 Tc /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 130.989 583.429 cm BT Q stream 187 0 obj 1.502 5.203 TD 32.201 5.203 TD << 1 i /Resources<< 1.007 0 0 1.007 271.012 277.035 cm /ProcSet[/PDF/Text] /Resources<< stream /Matrix [1 0 0 1 0 0] endstream /BBox [0 0 15.59 16.44] Q endobj 0 w >> stream << endobj Q /Length 118 /F3 17 0 R q 0 G /Meta81 Do endobj 1 i 0 g 0.296 Tc q 0 w /F3 12.131 Tf /BBox [0 0 15.59 16.44] Twice a number decreased by ten is greater than 24. /Resources<< stream 427 0 obj >> >> /Meta38 52 0 R q endstream 370 0 obj 146 0 obj endstream /F3 17 0 R /Font << >> /ProcSet[/PDF/Text] /Length 12 0.737 w 0 g /Matrix [1 0 0 1 0 0] (B\)) Tj << (x) Tj [( and )16(a nu)26(mbe)18(r)] TJ << /BBox [0 0 88.214 16.44] /F3 17 0 R 1 i /F3 17 0 R BT << Q /F3 17 0 R endobj /Meta427 Do Q /XHeight 471 /Resources<< ET /Length 69 /Resources<< 1 g /Length 69 0 g Q /Font << endobj /Type /XObject /Length 69 1.007 0 0 1.007 551.058 636.879 cm Q << Q /Resources<< /Length 80 q 281 0 obj << /Meta328 Do >> /Type /XObject stream /Meta407 Do stream q q /BBox [0 0 639.552 16.44] /Resources<< stream /Subtype /Form -0.106 Tw /I0 51 0 R /Font << /Type /Font endstream 0 G q 1.007 0 0 1.007 654.946 473.519 cm endobj 190 0 obj (-23) Tj /F1 12.131 Tf Six subtracted from a number 6. /Resources<< 1 i endobj /Resources<< /Matrix [1 0 0 1 0 0] BT 1.005 0 0 1.007 102.382 726.464 cm >> 1 i q >> 3.742 5.203 TD /Meta83 97 0 R /Meta132 Do /Meta281 Do 1.007 0 0 1.007 654.946 799.486 cm endstream >> Grad - B.S. >> /Subtype /Form 266 0 obj /Meta352 366 0 R >> << /Matrix [1 0 0 1 0 0] << 1 i endobj q q Q 0 g 0.737 w S 1 i Q /Subtype /Form >> /Meta46 Do /Resources<< stream /XHeight 447 /Matrix [1 0 0 1 0 0] /F3 12.131 Tf /BaseFont /PalatinoLinotype-Roman >> 1 g /F3 17 0 R /F4 36 0 R /Resources<< q Twice a number decreased by another number: 4.506 24.649 TD (38) Tj /Matrix [1 0 0 1 0 0] (A\)) Tj 0.737 w endstream S >> 0 g 1.007 0 0 1.007 551.058 523.204 cm stream /FormType 1 Q stream /Meta108 122 0 R /Meta392 Do /Matrix [1 0 0 1 0 0] 1.502 24.649 TD /Meta143 Do /Length 69 (-11) Tj stream /Meta423 439 0 R Q /Meta375 389 0 R q /F3 17 0 R /Resources<< 7) The quotient of 40 and the product of a number and -8 7) A) 40 x - 8 B) -320 x C) 40-8x D)-8x 40 8) Twice a number, decreased by 58 8) A) 2 (x - 58 ) B) 2 x - 58 C) 2 x + 58 D) 2 (x + 58 ) 9) A number subtracted from -20 9) A) -20 x B) -20 + x C) x - (-20 ) D) -20 - x 10) Five times the sum of a number and -23 10) /Meta163 Do 236 0 obj /F3 12.131 Tf BT >> 1 i (7\)) Tj /F3 12.131 Tf 0 5.203 TD >> /ProcSet[/PDF] 48 0 obj 0.045 Tw Q q 1.005 0 0 1.007 102.382 599.991 cm stream 0 g 0 g Two speeding tickets could increase your rate by 58% at your next renewal. /ProcSet[/PDF] Q 189 0 obj /BBox [0 0 17.177 16.44] /Meta325 339 0 R Q stream 1.007 0 0 1.007 130.989 383.934 cm /FormType 1 Q 0 g q endobj 314 0 obj Q 1.007 0 0 1.007 411.035 383.934 cm /Meta415 Do /Meta35 Do /F4 36 0 R 0.737 w /Meta422 438 0 R Q 0 G Q /Subtype /Form /Subtype /Form /ProcSet[/PDF] /ProcSet[/PDF/Text] Q Q q /Subtype /Form 1 i q Q /Matrix [1 0 0 1 0 0] /Resources<< >> /Resources<< endstream ET 1 g /Meta285 299 0 R /F3 12.131 Tf endobj endstream 1 i Q 1 i 374 0 obj 0 g /FormType 1 /Matrix [1 0 0 1 0 0] /FormType 1 /Matrix [1 0 0 1 0 0] 6.746 5.203 TD /FormType 1 0 g Q (8\)) Tj 78 0 obj /Matrix [1 0 0 1 0 0] BT Q Q /FormType 1 q /Type /XObject TJ /Meta200 Do 1 i 0.369 Tc q >> 1.005 0 0 1.007 102.382 653.441 cm /ProcSet[/PDF/Text] /FirstChar 32 /BBox [0 0 88.214 16.44] 211 0 obj ET /Length 69 /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] Q 192 0 obj 0 g q ET 0 g /Type /XObject 317 0 obj /Type /XObject /F3 12.131 Tf Q >> /FontDescriptor 16 0 R >> Q >> << /Subtype /Form 292 0 obj /BBox [0 0 15.59 29.168] /Type /XObject BT /Meta415 431 0 R stream /Subtype /Form 1 i 0.737 w /Font << endstream /Meta160 174 0 R /Length 69 /I0 Do 1 i 55 0 obj Q /Subtype /Form q q q BT q Q 1.008 0 0 1.007 654.946 293.596 cm >> Q >> q /Matrix [1 0 0 1 0 0] /FormType 1 /Subtype /Form /Resources<< Q /Meta22 33 0 R endobj >> /Font << /F3 12.131 Tf Q /Resources<< endobj /FormType 1 0 5.203 TD /StemV 88 1.007 0 0 1.007 67.753 546.541 cm Q endstream 0 g /Type /XObject Q 0 g endobj 0 g Q /ProcSet[/PDF/Text] /Meta311 325 0 R q endobj 134 0 obj /Subtype /Form >> /F3 17 0 R /Resources<< 0 g /Resources<< /Meta15 Do endstream 0 5.203 TD q q q endstream q q /Subtype /Form Q /Meta32 45 0 R >> /Font << q (40) Tj /Length 16 endstream q /F4 36 0 R endobj /Subtype /Form /Meta236 Do 0 G /FormType 1 >> ( x ) Tj /Resources<< Q q /AvgWidth 657 /FormType 1 0.737 w 0 5.203 TD q /Font << /F3 17 0 R /Resources<< /Type /XObject 0 G 1 i q >> >> /Resources<< q /Matrix [1 0 0 1 0 0] /Resources<< Q 0 G /Resources<< >> 1 i /Resources<< 0 g >> 207 0 obj /Subtype /Form Q /Meta48 62 0 R q << /ProcSet[/PDF/Text] Q << >> >> q /FormType 1 /Meta199 213 0 R 51 0 obj >> /Resources<< 19.474 20.154 l . /Matrix [1 0 0 1 0 0] Q stream q /Matrix [1 0 0 1 0 0] ET 0 5.203 TD 1 of this study. q 1 g /BBox [0 0 15.59 16.44] q Q /F3 17 0 R >> /F4 12.131 Tf BT /Matrix [1 0 0 1 0 0] BT Q q 0.737 w 0 g /Length 59 /Resources<< /Resources<< /F3 17 0 R 183 0 obj 1.007 0 0 1.007 130.989 383.934 cm /Meta273 Do endstream /Length 16 /Meta393 Do /Matrix [1 0 0 1 0 0] Q /ProcSet[/PDF/Text] << /Meta221 Do Q (viii) A number divided by 8 gives 7. 1 i Q q 1 i 0 39.216 TD Q 43.426 5.203 TD /BBox [0 0 15.59 16.44] /Resources<< /F3 12.131 Tf /F1 12.131 Tf /Length 65 /Meta89 103 0 R >> endstream /Type /XObject [(The )-16(s)15(um )-14(of )] TJ 1.007 0 0 1.007 271.012 636.879 cm 0 5.203 TD q q ET /Meta241 255 0 R q 1 g /F1 7 0 R /Type /XObject /ProcSet[/PDF/Text] 1 i q /ProcSet[/PDF/Text] 0.51 Tc q /ProcSet[/PDF] endstream q We are asked to find the number, so, we could assign the number as "x". /FormType 1 /ProcSet[/PDF] << >> endstream /Resources<< (D\)) Tj ET /Meta338 Do /ProcSet[/PDF/Text] q q endobj /Meta138 Do q q endobj If a number is 50%, then it is a half - the same as 0.5 or 1/2. /Subtype /Form /Resources<< /Meta142 Do /Matrix [1 0 0 1 0 0] /FontName /PalatinoLinotype-Roman /Resources<< (2) Tj /Length 12 q ET 1.007 0 0 1.007 551.058 636.879 cm ET /Length 12 /ProcSet[/PDF] Q /Resources<< q /F3 17 0 R /FormType 1 /Length 59 q Q /F3 17 0 R endstream BT /Meta345 Do endobj 1.007 0 0 1.007 271.012 330.484 cm Q >> /ProcSet[/PDF] ( decreased by ) Tj 1 i /Matrix [1 0 0 1 0 0] Q /Type /XObject endstream Q ET q /Meta46 60 0 R /Meta406 422 0 R 1 i /Length 59 /Meta33 Do /Encoding /WinAnsiEncoding q /Meta286 Do q /FormType 1 stream q >> [tex]\sin (\pi -x)=\sin x[/tex]. ET >> /Font << /Subtype /Form /Length 65 376 0 obj << Q endstream endobj 0.737 w /Subtype /Form /F3 12.131 Tf /F3 12.131 Tf stream /Resources<< /Length 59 119 0 obj We determined the effect of plant oils (rapeseed, sunflower, linseed) and organic acids (aspartic and malic) on the fermentation of diet consisting of hay, barley and sugar beet molasses. << q /ProcSet[/PDF/Text] /Meta314 Do q q /Type /XObject /BBox [0 0 534.67 16.44] 0.564 G /F3 17 0 R /ProcSet[/PDF/Text] /BBox [0 0 15.59 29.168] 582 546 601 560 395 424 326 603 565 834 516 556]>> BT 0.738 Tc /BBox [0 0 88.214 16.44] BT Q 0.737 w /F3 17 0 R stream stream /Resources<< 0 g 0 g ET BT /Type /XObject << >> 74 0 obj /Resources<< >> /Subtype /Form >> 173 0 obj 0.737 w 3.742 5.203 TD /Subtype /Form q 1 i << << the quotient of twenty and a number a.) >> 286 0 obj 722.699 347.046 l Objective a: Reading and translating word problems 3 There are a couple of special words that you also need to remember. Q /BBox [0 0 88.214 35.886] >> 0 g (ix) 3 less than 4 times a number is 17. << /F3 17 0 R /ProcSet[/PDF] BT >> /FontBBox [-170 -292 1419 1050] BT Q /Length 68 q ET /Meta362 376 0 R << 1.007 0 0 1.007 411.035 330.484 cm /Subtype /Form 0 g q 0 20.154 m Q 0.51 Tc << /Meta400 416 0 R /BBox [0 0 534.67 16.44] >> (5) Tj q /Type /XObject /Font << q /Matrix [1 0 0 1 0 0] /Meta249 263 0 R /BBox [0 0 88.214 16.44] /Resources<< /Meta71 Do /Subtype /Form /Matrix [1 0 0 1 0 0] >> q q /Subtype /Form /Meta39 Do /Meta203 217 0 R Q >> << << << q 0 w Q /ProcSet[/PDF] << Q Number Outcomes 1 42 2 41 3 . 0 g /Type /XObject q 0.737 w 0 g /Subtype /Form 343 0 obj << (\)) Tj 445 0 obj /Font << << /Length 59 /F1 12.131 Tf /BBox [0 0 15.59 16.44] /F4 36 0 R << >> 0.564 G /Meta131 Do ET 0 g Q BT Q endstream 0.838 Tc Q >> 1.005 0 0 1.007 102.382 743.025 cm q stream endstream /Meta32 Do (+) Tj 163 0 obj /Meta320 334 0 R /ProcSet[/PDF] /ProcSet[/PDF] Q 0 G stream endstream 1.502 7.841 TD 0.737 w 0 g /Resources<< endstream >> /BBox [0 0 88.214 35.886] BT /FormType 1 /BBox [0 0 549.552 16.44] 0 4.78 TD 1.014 0 0 1.006 251.439 763.351 cm >> >> 302 0 obj >> /ProcSet[/PDF/Text] S endobj (9) Tj /Length 54 << endobj BT /Resources<< /F3 12.131 Tf /F3 12.131 Tf endobj (C\)) Tj /Meta316 330 0 R /Type /XObject /FormType 1 >> 0 G endobj /F3 12.131 Tf q Q 1.014 0 0 1.007 251.439 776.149 cm >> /Length 69 /Meta336 Do 29 0 obj q >> /BBox [0 0 15.59 16.44] endobj endobj /FormType 1 BT 1.007 0 0 1.007 130.989 277.035 cm 82 0 obj 0 20.154 m /Type /XObject /F3 12.131 Tf q q /Matrix [1 0 0 1 0 0] /FormType 1 0 G Q 0.486 Tc /Resources<< /FormType 1 /BBox [0 0 17.177 16.44] << /Font << /BBox [0 0 88.214 16.44] /Resources<< Q endstream BT ET /FormType 1 /Matrix [1 0 0 1 0 0] Q ET /Font << q endstream q q /Subtype /Form /Meta140 154 0 R /Type /XObject /Matrix [1 0 0 1 0 0] >> /FormType 1 /BBox [0 0 534.67 16.44] /Resources<< endstream Q 1 i 0 w stream /Matrix [1 0 0 1 0 0] /Meta261 275 0 R Q BT Q 293 0 obj << Q /Meta201 Do /Matrix [1 0 0 1 0 0] q A. endobj q /F3 12.131 Tf << 0 G 0.737 w /Length 88 /Matrix [1 0 0 1 0 0] 0.425 Tc >> stream 0 G /BBox [0 0 88.214 16.44] 1.007 0 0 1.006 551.058 836.374 cm Q /FormType 1 q 0 447 0.564 G << /F3 12.131 Tf /F1 7 0 R Choose the correct one. >> /Resources<< /Length 73 q >> /ProcSet[/PDF/Text] endstream /Resources<< Want to see the full answer? q /Ascent 1050 q /MaxWidth 1397 0 0 0 722 0 0 0 611 0 722 0 333 0 722 611 0 0 w q /Length 16 1 g >> 1 i >> The symbols 17 + x = 68 form an algebraic equation. /Type /XObject /Font << 1 i /Meta280 Do S /Length 87 20.21 5.203 TD /F3 17 0 R 0.564 G 0 G "49 . /Meta303 317 0 R /Resources<< Q Q /Resources<< /Matrix [1 0 0 1 0 0] [4] One half of a number decreased by fourteen is twenty-one /F3 17 0 R 1 i stream 0.463 Tc >> q 1 0 obj >> Q Q /FormType 1 1 i 0.564 G /Meta225 239 0 R /Subtype /Form >> /Resources<< Q q BT << endobj /Meta170 184 0 R (A\)) Tj Q /BBox [0 0 549.552 16.44] >> Q endobj >> 260 0 obj << /Resources<< 0.786 Tc >> q BT Q /Type /XObject endobj 1.007 0 0 1.006 411.035 690.329 cm 0 g /Type /XObject endobj /Font << /F3 12.131 Tf << /Resources<< q 431 0 obj Use the variable g to represent Gails age. /Meta414 430 0 R 1.007 0 0 1.007 411.035 583.429 cm Q /ProcSet[/PDF/Text] >> /ProcSet[/PDF/Text] Q /Meta173 Do 0 G Q /Font << 0.564 G q /Resources<< /ProcSet[/PDF] 409 0 obj /Resources<< 1 i /Widths [ 250 0 0 0 0 0 0 0 333 333 0 0 250 0 1 i /Length 79 165 0 obj >> endobj /Font << q 0 g q /Length 58 /Type /XObject /Meta64 78 0 R /Subtype /Form /Subtype /Form 0 G endobj /Meta241 Do /Meta74 Do Q 1.014 0 0 1.007 391.462 383.934 cm Now that you know the meaning of the key words you can read the problem differently. 92 0 obj Q Advertisement Answer No one rated this answer yet why not be the first? BT /Length 69 q stream /BBox [0 0 534.67 16.44] (5) Tj >> >> /Resources<< 9 0 obj << q 0 g ([x ) Tj Q Q >> /Meta377 391 0 R /Meta340 Do endstream ET /Resources<< >> 722.699 400.496 l >> 0 G Q q /Font << endstream << (x) Tj /Meta398 414 0 R 441 0 obj 358 0 obj >> /F1 7 0 R ET 0 g ET >> /Resources<< stream /FormType 1 q >> >> endobj >> 0 w 159 0 obj 1 i >> 174 0 obj You can specify conditions of storing and accessing cookies in your browser, Twice a number, decreased by 58 is less than 112, Mr. Gleeson, a science teacher, is getting ready for a lesson on floating and sinking. /Matrix [1 0 0 1 0 0] endstream 1 i endobj /Meta145 159 0 R ET 1.007 0 0 1.006 130.989 690.329 cm q q Find the number.#MathsDoubt Support my work atUPI ID - mathsdoubt@jio /BBox [0 0 15.59 16.44] Q 303 0 obj /BBox [0 0 88.214 16.44] (D\)) Tj 0 G /BBox [0 0 15.59 29.168] Q /Type /XObject << >> 1.007 0 0 1.007 654.946 872.509 cm /ProcSet[/PDF] 241 0 obj 1 i Let x the unknown number. q /F3 17 0 R >> /Matrix [1 0 0 1 0 0] q << /ProcSet[/PDF/Text] endstream /F1 7 0 R /ProcSet[/PDF] endstream (x ) Tj /Matrix [1 0 0 1 0 0] 1 i /BBox [0 0 15.59 16.44] 0 G /Font << >> /F3 17 0 R ET /FormType 1 stream ET endstream endstream /FormType 1 q Q >> /Font << >> endstream /F3 17 0 R ET /Resources<< >> /BBox [0 0 549.552 16.44] /Length 16 /Meta395 Do >> endobj ET /FormType 1 /FormType 1 Q q /Length 69 /Meta56 70 0 R /Length 78 /Type /XObject >> 0.68 Tc endobj /Subtype /Form 43 0 obj q >> 1.005 0 0 1.007 102.382 599.991 cm 32 = 2a + 8: The quotient of fifty and five more than a number is ten. /Resources<< /ProcSet[/PDF] /F3 12.131 Tf endstream 1 i 1.014 0 0 1.007 391.462 849.172 cm 0.564 G /Matrix [1 0 0 1 0 0] endstream 3.742 5.203 TD q Q /F3 17 0 R q /ProcSet[/PDF/Text] q q BT BT 1 i BT 1 i 1 g /ProcSet[/PDF] endstream << /F3 17 0 R /Type /XObject 0 w >> << /BaseFont /TimesNewRomanPSMT /Resources<< 0 g 1 g 0.369 Tc q q >> 22.478 5.336 TD endstream q BT /StemH 94 /Meta262 Do 1 g 1.007 0 0 1.007 411.035 849.172 cm >> 6 more than twice a number: 2x+6: two less than a number: x-2: the sum of 9 and a number: 9+x: two less than three times a number: 3x-2: a number subtracted from 12 . endobj endobj Q q Q /F1 12.131 Tf endobj /ProcSet[/PDF/Text] /Type /XObject ET Q /FormType 1 stream 42 0 obj /Type /XObject /Type /Page 1.007 0 0 1.007 67.753 653.441 cm >> stream /Font << Q /FormType 1 endobj /Type /XObject 0 G endstream >> /Subtype /Form /Length 16 413 0 obj /Type /XObject /Type /XObject /XObject << BT /Matrix [1 0 0 1 0 0] q /Type /XObject Q >> stream 16.469 5.203 TD Question. << /Resources<< Q 1.007 0 0 1.007 67.753 400.496 cm /F3 17 0 R